Re: cannot locate syntax error in urls.py

My bad. Thanks for the quick hint, turns out I was not looking the right way.. On 23 Apr, 16:42, Daniel Roseman wrote: > On Monday, 23 April 2012 15:03:35 UTC+1, r0pewalker wrote: > > > Hi everybody. I recently started working on a project involving heavy > > Django usage. > > I basically retriev

Re: cannot locate syntax error in urls.py

On Monday, 23 April 2012 15:03:35 UTC+1, r0pewalker wrote: > > Hi everybody. I recently started working on a project involving heavy > Django usage. > I basically retrieve data in xml from a SOAP web service using suds, > parse the xml into a db and then (I should) popuate a web page. > I'm a

cannot locate syntax error in urls.py

Hi everybody. I recently started working on a project involving heavy Django usage. I basically retrieve data in xml from a SOAP web service using suds, parse the xml into a db and then (I should) popuate a web page. I'm a beginner both in Python and Django, please bear with me and my possibly ill

Re: error in urls.py

Thanks that resolved. On May 3, 5:41 pm, Daniel Roseman wrote: > On May 3, 8:27 am,andysaksena wrote: > > > > > Hi > > > my urls.py is > > > from django.conf.urls.defaults import * > > > # Uncomment the next two lines to enable the admin: > > from django.contrib import admin > > admin.autodisco

Re: error in urls.py

On May 3, 8:27 am, andy saksena wrote: > Hi > > my urls.py is > > from django.conf.urls.defaults import * > > # Uncomment the next two lines to enable the admin: > from django.contrib import admin > admin.autodiscover() > > urlpatterns = patterns(”, > # Example: > # (r’^/’, include(‘.foo.u

error in urls.py

Hi my urls.py is from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns(”, # Example: # (r’^/’, include(‘.foo.urls’)), (r’^accounts/’, include(‘registration.backends.default