Never mind. Clearly, I was confusing my models with my forms.
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I have a model field that I want to change the attrs on when displayed
by newforms. I thought I could do something like:
class Timesheet(models.Model):
date = DateField(widget=forms.TextInput())
and then define my attrs in the widget. But syncdb is complaining:
TypeError: __init__() got
On Sat, Apr 29, 2006 at 08:20:30PM -0500, James Bennett wrote:
> In the tutorial, the field on the Choice model ('poll') is the same as
> the name of the model it's being related to ('poll'), which is why it
> looks that way. Whenever they're different, you want to use the name
> of the field on
On 4/29/06, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> This is not what I understood from reading and practicing the tutorial
> 1:
In the tutorial, the field on the Choice model ('poll') is the same as
the name of the model it's being related to ('poll'), which is why it
looks that way.
gt; from within a view, I get:
>
> TypeError at /cadastro/pesquisa/
> got unexpected keyword argument 'servicos__id__exact'
Hi Luis,
When using the Django database API, you use the field names, not the
model names. So you want this:
cadastros.get_list(serv_clientes__id__exa
This is not what I understood from reading and practicing the tutorial
1:
# The API automatically follows relationships as far as you need.
# Use double underscores to separate relationships.
# This works as many levels deep as you want. There's no limit.
# Find all Choices for any poll whose
Luis P. Mendes wrote:
>As _django models_:
>class Servico(meta.Model):
>~codigo = meta.TextField(maxlength=4)
>~nome = meta.CharField(maxlength=80)
>
>~def __repr__(self):
>~return self.nome
>
>class Cadastro(meta.Model):
>~serv_clientes =
_(self):
~return self.nome
class Cadastro(meta.Model):
~serv_clientes = meta.ForeignKey(Servico)
~nome = meta.CharField(maxlength=200)
~ (...)
~ def __repr__(self):
~return self.nome
when I try:
lista_sps = cadastros.get_li
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