Re: how to activate DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST

Thanks a lot, i did miss to pass context_instance=RequestContext(request) in my view code def access(request): return render_to_response('tool.html',context_instance=RequestContext(request)) after I added "context_instance=RequestContext(request)" It is working now like a charm!

Re: how to activate DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST

On Thu, Feb 4, 2010 at 2:39 PM, weiwei wrote: > Thanks.. > > Here is my code > > You repeated the code for the template tag and the context processors setting; that's not what I asked for. I still don't see the code for the view that renders the template that

Re: how to activate DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST

Thanks.. Here is my code from django import template from django.template import RequestContext register = template.Library() @register.inclusion_tag('userinfo.html',takes_context = True) def userinfo(context): request = context['request'] address = request.session['address']

Re: how to activate DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST

On Thu, Feb 4, 2010 at 1:41 PM, weiwei wrote: > "DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST > If TEMPLATE_CONTEXT_PROCESSORS contains this processor, every > RequestContext will contain a variable request, which is the current > HttpRequest. Note that this processor is

how to activate DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST

"DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST If TEMPLATE_CONTEXT_PROCESSORS contains this processor, every RequestContext will contain a variable request, which is the current HttpRequest. Note that this processor is not enabled by default; you'll have to activate it. " from this page