Thanks for your reply, I really like the general iterator approach.
This recipe will definitely go to my personal "standard" library.
A.
On Dec 2, 11:09 pm, Tim Chase <[EMAIL PROTECTED]> wrote:
> > If your data is in the 'data' context variable, then try this:
>
> >
> > {% for
> If your data is in the 'data' context variable, then try this:
>
>
> {% for d in data %}
> {% if forloop.counter0|divisibleby:"2" %}{% endif %}
> {{d}}
> {% if forloop.counter|divisibleby:"2" %}{% endif %}
> {% endfor %}
> {%
If your data is in the 'data' context variable, then try this:
{% for d in data %}
{% if forloop.counter0|divisibleby:"2" %}{% endif %}
{{d}}
{% if forloop.counter|divisibleby:"2" %}{% endif %}
{% endfor %}
{% if
On Sun, 2007-12-02 at 03:05 -0800, andrej kesely wrote:
> hi,
> i have small question:
> suppose i have data in QuerySet - ['A', 'B', 'C', 'D', 'E', 'F',
> 'G'].
> I want make from this set two-column table in my template:
>
> AB
> CD
> EF
> G
>
> What is the fastest way to
On Dec 2, 1:05 pm, andrej kesely <[EMAIL PROTECTED]> wrote:
> hi,
> i have small question:
> suppose i have data in QuerySet - ['A', 'B', 'C', 'D', 'E', 'F',
> 'G'].
> I want make from this set two-column table in my template:
>
> AB
> CD
> EF
> G
>
> What is the fastest way
hi,
i have small question:
suppose i have data in QuerySet - ['A', 'B', 'C', 'D', 'E', 'F',
'G'].
I want make from this set two-column table in my template:
AB
CD
EF
G
What is the fastest way to do it? I don't want split the QuerySet in
my views to something like this: [(A,
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