models.FileField realy requires `upload_to` param. And it can be callable
with `instance` argument [1]. Using this feature you can generate upload
path by the instance fields.
[1]: http://docs.djangoproject.com/en/dev/ref/models/fields/#filefield
On Thu, Dec 11, 2008 at 13:47, Alan <[EMAIL PROTEC
Hello there!
So, I am trying to build a model and from it build a form. I have something
like:
class Job(models.Model):
juser = models.CharField(max_length=40)
jname = models.CharField(max_length=255)
title = models.CharField(max_length=255, null=True, blank=True)
file = models
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