On Sun, Jul 9, 2017 at 8:43 AM, Gustavo A. R. Silva
wrote:
> The assignment operator implicitly converts a void pointer to the type of the
> pointer it is assigned to.
>
> This issue was detected using Coccinelle and the following semantic patch:
>
> @@
> expression * e;
> expression arg1, arg2;
>
The assignment operator implicitly converts a void pointer to the type of the
pointer it is assigned to.
This issue was detected using Coccinelle and the following semantic patch:
@@
expression * e;
expression arg1, arg2;
type T;
@@
- e=(T*)
+ e=
kmalloc(arg1, arg2);
Signed-off-by: Gustavo A. R