"H. Noedl" wrote:
Unfortunately my knowledge of statistics is rather limited to the basics
(i.e. regression, t-test etc.). I tried by transforming the drug
concentration into NLog (LN(x)) and the response into probits
(NORMSINV(x)+5) and doing an ordinary linear regression (y=a+bx) to
Robert Lienhart wrote:
I want to make a mean comparison with two test groups( every person is
tested twice).
The problem is, this is an ADAPTIV testing; which means that every
person has different absolute results, e.g.
In general I'd say no. The thing with adaptive testing
is that the
