"Derek Ross" <[EMAIL PROTECTED]> wrote:
> I have four coins in my hand. Each coin has a number on both sides.
> All coins have a zero on one side, and the other side has a number
> from 1 to 4.
>
> I then hurl the handful of coins at the ground, then add up the
> values of all the coins. [...]
On 24 Dec 2000 08:04:17 -0500, [EMAIL PROTECTED] (Herman
Rubin) wrote:
>If there is a simple form, it will involve using results
>from some version of number theory. The generating function
>of the total is (\prod_1^n (1+x^k) )/2^n. If the mean n(n+1)/2
>is subtracted, the characteristic functio
In article ,
Derek Ross <[EMAIL PROTECTED]> wrote:
>This is an odd distribution... I think it may somehow be related to the
>binomial distribution, but I'm not certain.
>The idea is difficult to explain, so here's a "real-life" example of
>generating the distributio
Two comments:
(1) If the coins are numbered (on the non-zero side) 1, 2, 4, 8, ...
then each possible total occurs exactly once. If Derek's coins are
labelled 0 and X (X = 1, 2, 3, ...), these new coins are labelled 0 and
2^(X-1). I don't know if this observation is helpful, since I don't
This is an odd distribution... I think it may somehow be related to the
binomial distribution, but I'm not certain.
The idea is difficult to explain, so here's a "real-life" example of
generating the distribution:
I have four coins in my hand. Each coin has a number on both sides. All
coins have