Thanks for the formula, but I was really interested in knowing what % of a
standard deviation corresponds to E.
In other words does a .02 error translate into .02/1 standard deviations?
"Graeme Byrne" <[EMAIL PROTECTED]> wrote in message
9orn26$m80$[EMAIL PROTECTED]">news:9orn26$m80$[EMAIL PROT
This sounds like homework but I will .
Anyway assume the normal approximation to the binomial can be used (is this
reasonable?) then the formula for estimating sample sizes based on a given
confidence level and a given maximum error is
n = z*Sqrt(p*(1-p))/e
where z = the z-scores associated wit
If you have a confidence level of 90% and an error estimate of 4% and don't
know the std deviation, is there a way to express the error estimate as a
fraction of a std deviation?
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