[EMAIL PROTECTED] (John Uebersax) wrote:
> Both the PHI() and probit() functions are well approximated in
> simple applications (such as calculating confidence intervals)
> by simple polynomial formulas of a few terms. Some of these
> take as few as 2 or 3 lines of code.
You can find an approxi
Hi Stefan,
"s.petersson" <[EMAIL PROTECTED]> wrote in message
news:...
> Let's say I want to calculate this constant with a security level of
> 93.4563, how do I do that? Basically I want to "unfold" a function like
> this:
>
> f(95)=1.96
>
> Where I can replace
: "s.petersson" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, July 04, 2001 11:11 AM
Subject: How calculate 95%=1.96 stdv
> Hi NG,
>
> I sometimes run into a constant of 1.96 stdv that is used to calculate 95%
> statistical confidence intervals. But I ca
At 01:11 PM 7/4/01 +, s.petersson wrote:
>Hi NG,
>
>I sometimes run into a constant of 1.96 stdv that is used to calculate 95%
>statistical confidence intervals. But I can't seem to find how the 1.96 stdv
>is actually derived from a security level of 95%. In the statistical
>textbooks I've rea
s.petersson <[EMAIL PROTECTED]> wrote:
> I sometimes run into a constant of 1.96 stdv that is used to calculate 95%
> statistical confidence intervals. But I can't seem to find how the 1.96 stdv
> is actually derived from a security level of 95%. In the statistical
> textbooks I've read, there is
Hi NG,
I sometimes run into a constant of 1.96 stdv that is used to calculate 95%
statistical confidence intervals. But I can't seem to find how the 1.96 stdv
is actually derived from a security level of 95%. In the statistical
textbooks I've read, there is only a huge table with different stdv's