Here's a quick puzzle, that'd make a good source of Python programs,
or programs in other languages:
Assume dogs live at 7 times the rate of a man, such that when a man
ages but one year, the dog ages by 7. Now assume a dog is born later
than you, and you get her as a puppy (feel free to mess
# I love Python!
import datetime# batteries included!
me = datetime.date(1954,9,1)
dog = datetime.date(2006,3,7)
print me + (7 * (dog - me)/6)
# mt
On 3/7/06, kirby urner [EMAIL PROTECTED] wrote:
Here's a quick puzzle, that'd make a good source of Python programs,
or programs in other
[kirby urner]
Here's a quick puzzle, that'd make a good source of Python programs,
or programs in other languages:
Assume dogs live at 7 times the rate of a man, such that when a man
ages but one year, the dog ages by 7
That vaguely reminds me of a puzzle I enjoyed much as a kid: on
Yeah, that looks like the Jon Bunce formula. Packing lap top. Hoping
to claim $5 (I owe you a beer).
Kirby
On 3/7/06, Michael Tobis [EMAIL PROTECTED] wrote:
# I love Python!
import datetime# batteries included!
me = datetime.date(1954,9,1)
dog = datetime.date(2006,3,7)
print me +
Michael --
Here's a cut and paste from Pauling House (boyhood home of Portland
*other* famous Linus).
IDLE 1.1.1
import datetime
me = datetime.date(1952,12,17)
dog = datetime.date(1999, 1,2)
print me + (7 * (dog - me)/6)
2006-09-04
This is the real answer the guy wanted. Mission
Tim Peters wrote:
That vaguely reminds me of a puzzle I enjoyed much as a kid: on what
day will you be half as old as your father? a third as old? a
quarter as old? three-quarters as old? nine-tenths as old? ... It's
a good way of showing that x/(x+d), for fixed positive d, approaches 1
This is the real answer the guy wanted. Mission accomplished. No
offer of $5 though.
Kirby
Still here at Pauling House (near 39th Hawthorne, SE Portland). The
dog owner remembered about the $5. I said I'm narrating the story in
quasi real time, that his giving me a fiver would enter the
