On Oct 31, 2011, at 8:16 AM, election-methods-requ...@lists.electorama.com
wrote:
> I entered your example into the (free) VoteFair-ranking service at
> VoteFair.org and here is the results page:
>
> http://www.votefair.org/cgi-bin/votefairrank.cgi/votingid=10305-48109-09917
>
> VoteFair popul
On 10/28/2011 2:21 PM, capologist wrote:
> > ...
> Not quite what I'm looking for. ...
> ...
> I'm looking for a deterministic method for generating a "picture"
> (partial ordering) of how the voters, in aggregate, feel about the
> preferability of the available options. (What we're doing at this
capologist wrote:
I'm no expert in this field, but it is one I find interesting and
visit from time to time. My first encounter with it was when I
stumbled on a website advocating what was then called the Tideman
method, before it was called Ranked Pairs and before the Schulze
method was discover
On Oct 29, 2011, at 12:29 AM, Kristofer Munsterhjelm wrote:
> you could (for instance) break them in Ranked Pairs order.
>
> A Ranked Pairs tiebreak is fully deterministic. Sort the victories in order
> of magnitude, then if M1 > M2 comes before M2 > M1, set M1 above M2. It may
> feel hackish t
capologist wrote:
See section 5 of my paper:
Not quite what I'm looking for. That section describes a
non-deterministic method for generating a complete linear order.
I don't require a linear order. I'm OK with a partial ordering.
I'm looking for a deterministic method for generating a "pictu
Hallo,
> Not quite what I'm looking for. That section describes
> a non-deterministic method for generating a complete
> linear order.
Well, although this tie-breaking strategy is _formulated_
as a random tie-breaker, it is almost always decisive.
Markus Schulze
Election-Methods mailing l
FYI, the Condorcet-Kemeny method correctly ranks M1 as second-most
popular, and M2 as third-most popular. And it does so without the need
for a "tie-breaker" adjustment.
Richard Fobes
On 10/27/2011 8:46 PM, capologist wrote:
I recently conducted a vote under the Schwartz method. It produced
> See section 5 of my paper:
Not quite what I'm looking for. That section describes a non-deterministic
method for generating a complete linear order.
I don't require a linear order. I'm OK with a partial ordering.
I'm looking for a deterministic method for generating a "picture" (partial
ord
Hallo,
as long as the used tie-breaking strategy guarantees
that M1 is ranked ahead of M2, I see no problem.
See section 5 of my paper:
http://m-schulze.webhop.net/schulze1.pdf
Markus Schulze
Election-Methods mailing list - see http://electorama.com/em for list info
I recently conducted a vote under the Schwartz method. It produced a result that is counterintuitive and that I don’t know how to justify.Here’s a simplified version of the scenario: 5x A > M1 = M2 > B 3x B > A > M1 = M2 2x M1 = M2 > B > A 2x M1 > M2 > B > AThe partial ordering produced
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