Forest suggests:
For each pair of candidates X and Y, let F(X,Y) be the number of ballots on
which X is ranked equal first with Y, plus the number of ballots on which X
is ranked ahead of Y.
Similarly, let L(X,Y) be the number of ballots on which X is equal last with
Y (i.e. on which neither i
Dear EM aficionados,
Here's a method that elects the candidate with the best ratio of offensive
strength to defensive weakness. Until a better name comes up, call it
Offense/Defense or O/D.
For each pair of candidates X and Y, let F(X,Y) be the number of ballots on
which X is ranked equal
