Regarding step 2. below, what if there is a three way tie like this:
winner loser strength
D C 20
B D 20
C B 17
A C 17
A D 17
B A 14
There is a cycle among the three losers BCD: C
Another opportunity to "advertise" the "margins" website and annoy M.O. here: The
Approval/Condorcet combination method Kevin mentions can be implemented using the
Condorcet PERL script found on sourceforge.net. The following generates the tally
matrix from the ballot list:
perl ballot2tally.pl
Another opportunity to "advertise" the "margins" website and annoy M.O. here: The
Approval/Condorcet combination method Kevin mentions can be implemented using the
Condorcet PERL script found on sourceforge.net. The following generates the tally
matrix from the ballot list:
perl ballot2tally.pl
