Thanks, folks! I'll save these messages forever. Oddly enough, it's
hard to find a manual entry that explains all the answers I got in that
much detail. Possible, mind you, but hard . . .
--Richard
On 2003.06.24 21:08 b wrote:
Richard,
This is the way I think of it. And you can extend this
Richard,
This is the way I think of it. And you can extend this logic to all your
dereferencing needs. Forgive me if I tell you things you already know.
A scalar is one "thing". ${}
An array is many things stacked together, one after the other. @{}
A hash is a set of named things %{}.
So I want
> Now, with hash references, you can do it two ways. $foo{whatever} is the
> same as $foo->{whatever}
I meant $$foo{whatever} is the same as $foo->{whatever} ;)
Patrick Galbraith wrote:
that's called a reference in perl
$foo = 'hu';
if I want to pass that as a reference to a subroutine (much
that's called a reference in perl
$foo = 'hu';
if I want to pass that as a reference to a subroutine (much better way
to do things than by value) I would do this:
speak(\$foo);
sub speak {
my ($foo) = @_;
# this is by reference "$$"
print $$foo . "\n";
# als
Just a quick question, and perhaps it's a Perl language question. I
forget, but why do you have to reference a hash with a double "$$" when
you use fetchrow_hashref?
[-
use DBI;
# code to open connection, run query, etc . . .
-]
[$ if $hashed_row = $query
