Following opinions are mine alone, and were heavily influenced by my lunch-time
burrito.
Looked at one about 10 years past and decided the design was, in my opinion,
'marginal' per scoped safety standards; but have not looked at any recent
product versions. Not accurate for high crest-factor st
Shameless plug follows: check out the "Auditor": DIN rail, 6 channels,
three phases, real-time over WiFi or 3G, highly configurable, Class 1,
UL61010, etc. around US$200 includes CTs.
Jon Keeble
wattwatchers.com.au
On Tue, Feb 13, 2018 at 8:36 AM, Brian O'Connell
wrote:
> Will admit to having do
Sent from my Verizon Wireless 4G LTE smartphone
Original message
From: Michael Derby
Date: 02/09/2018 4:54 PM (GMT-05:00)
To: "Schmidt, Mark" , EMC-PSTC@LISTSERV.IEEE.ORG
Subject: RE: [PSES] FCC 433 MHz
Original message
From: Michael Derby
Date: 02/09/2018
While on the subject, any one familiar with the Kill A Watt meter? This listing
sells for US$26 and free shipping:
https://www.amazon.com/P3-International-P4460-Electricity-Monitor/dp/B000RGF29Q
I swapped out the 2 mOhm current sensing resistor with a 0.2 ohm resistor (and
of course greatly lim
Will admit to having done this stuff with using microcontrollers and discrete
sequential data channels and of sufficient sampling speed, but am subject to
frequent bouts of idiocy. And this was for process control, and thus not a Type
Test. Also, note that there is a difference in technique and
VA. You don't have any phase information when the two variables are
measured separately.
Ghery
-Original Message-
From: Amund Westin [mailto:am...@westin-emission.no]
Sent: Monday, February 12, 2018 1:05 PM
To: EMC-PSTC@LISTSERV.IEEE.ORG
Subject: [PSES] Current measurement
If you want
Unless you can look at both voltage and current on an o'scope and compute
phase angle between them, you are only measuring apparent power.
Ken Javor
Phone: (256) 650-5261
> From: Amund Westin
> Reply-To: Amund Westin
> Date: Mon, 12 Feb 2018 22:04:44 +0100
> To:
> Subject: [PSES] Current mea
If you want to calculate the consumed power (W) in a 1-phase AC circuit, you
can use a current clamp-on device to measure the current in one lead/wire
and multiply with the applied voltage.
But with such a current clamp on device, to we measure the apparent power
(VA) or the real power (W)?
Best r
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