Re: Stephen Hawking: Philosophy is Dead

2012-07-15 Thread Stephen P. King
On 7/15/2012 2:34 AM, meekerdb wrote: On 7/14/2012 7:26 PM, Stephen P. King wrote: On 7/14/2012 8:47 PM, meekerdb wrote: On 7/14/2012 9:48 AM, Stephen P. King wrote: No, the reverse is the case. The "belongs to an infinity of computations making you singling out some stable patterns" requi

Re: Stephen Hawking: Philosophy is Dead

2012-07-15 Thread meekerdb
On 7/14/2012 8:15 PM, Stephen P. King wrote: And I need to add that not only is there a persistent "you", there is every possible version of that persistent "you". If there is Identity via fixed point, then there is a "you' involved in some capacity. I wrote there was no unique, persistent

Re: Stephen Hawking: Philosophy is Dead

2012-07-15 Thread John Mikes
Brent (and Stephen): (while I could not 'locate' the relation "on pain of circularity" - whether it is to explain , or ?) I identify an *'observer'* ANY*THING* accepting - A N Y info/relation, while *conscious(*ness) is generalized (IMO) to responding to such in ANY way. I agree with NOT assuming

Re: Stephen Hawking: Philosophy is Dead

2012-07-15 Thread John Clark
On Fri, Jul 13, 2012 at 5:18 PM, Craig Weinberg wrote: >>> The difference between names and numbers is that numbers can only be >>> augmented in a linear fashion >>> >> >> >> For all numbers x in set X let x=x^2 >> > > > That doesn't augment the variety of number types in set X, > It certainly au

Re: Stephen Hawking: Philosophy is Dead

2012-07-15 Thread John Clark
On Sat, Jul 14, 2012 at 11:15 PM, Stephen P. King wrote: >If there is Identity via fixed point, then there is a "you' involved in > some capacity. It just might not be belonging to an entity that some people > denote as "John Clark"; it could be "Atom of Hydrogen". This rule applies > to anything

Re: Stephen Hawking: Philosophy is Dead

2012-07-15 Thread John Clark
On Sat, Jul 14, 2012 at 1:55 PM, Stephen P. King wrote: > > > Could you tell us what you mean by "third parties" and "others"? Second parties. John K Clark -- You received this message because you are subscribed to the Google Groups "Everything List" group. To post to this group, send ema