On Fri, 2002-11-22 at 14:56, Todd Lyons wrote:
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> ath1410 wrote on Fri, Nov 22, 2002 at 05:04:55PM +0900 :
> >
> > I checked the sites you refered, but did not still quite figure
> > out (partly because of my poor English?) the way bash works the
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ath1410 wrote on Fri, Nov 22, 2002 at 05:04:55PM +0900 :
>
> I checked the sites you refered, but did not still quite figure
> out (partly because of my poor English?) the way bash works the
> way it does. To make things simple, just take up one case
ath1410 wrote:
>tks, Mr Larry.
>
>I checked the sites you refered, but did not still quite figure
>out (partly because of my poor English?) the way bash works the
>way it does. To make things simple, just take up one case here.
>
>$PS1=u -4 returns \u
>
>the 1st \ escapes the 2nd \,
tks, Mr Larry.
I checked the sites you refered, but did not still quite figure
out (partly because of my poor English?) the way bash works the
way it does. To make things simple, just take up one case here.
$PS1=u -4 returns \u
the 1st \ escapes the 2nd \,
Larry Sword wrote:
ath1410 wrote:
Can someone help! I have been trying to explain the way bash
works as follows.
$PS1=\\u -2 returns user
$PS1=\\\u-3 returns user
$PS1=u -4 returns \u
$PS1=\u -5 returns \u
$PS1=\\u -6 return
ath1410 wrote:
>Can someone help! I have been trying to explain the way bash
>works as follows.
>
>$PS1=\\u -2 returns user
>$PS1=\\\u-3 returns user
>$PS1=u -4 returns \u
>$PS1=\u -5 returns \u
>$PS1=\\u -6 returns \user
>$PS1=\\
Can someone help! I have been trying to explain the way bash
works as follows.
$PS1=\\u -2 returns user
$PS1=\\\u-3 returns user
$PS1=u -4 returns \u
$PS1=\u -5 returns \u
$PS1=\\u -6 returns \user
$PS1=\\\
