[firebird-support] Solution for a redundant join?

2012-10-24 Thread Jeff
The following simple query produces the results below: SELECT SCHEDULE.DATE_TIME, TEAMS.TEAM FROM SCHEDULE LEFT JOIN TEAMS ON SCHEDULE.HOME_TEAMID=TEAMS.PRIMARYKEY ***QUERY RESULTS (Showing 'Home Team' Column)*** 12/01/2012 TeamA 12/21/2012 TeamB 12/25/2012 TeamC How do I include the

RE: [firebird-support] Solution for a redundant join?

2012-10-24 Thread Leyne, Sean
The following simple query produces the results below: SELECT SCHEDULE.DATE_TIME, TEAMS.TEAM FROM SCHEDULE LEFT JOIN TEAMS ON SCHEDULE.HOME_TEAMID=TEAMS.PRIMARYKEY ***QUERY RESULTS (Showing 'Home Team' Column)*** 12/01/2012 TeamA 12/21/2012 TeamB 12/25/2012 TeamC How do I include

Re: [firebird-support] Solution for a redundant join?

2012-10-24 Thread Louis Kleiman (SSTMS, Inc.)
Try using aliases: SELECT SCHEDULE.DATE_TIME, HOME_TEAM.TEAM as HomeTeamName, AWAY_TEAM.TEAM as AwayTeamName FROM SCHEDULE LEFT JOIN TEAMS HOME_TEAM ON SCHEDULE.HOME_TEAMID=HOME_TEAM.PRIMARYKEY LEFT JOIN TEAMS AWAY_TEAM ON SCHEDULE.AWAY_TEAMID=AWAY_TEAM.PRIMARYKEY On Wed, Oct 24,