Am 24.02.2010, 20:55 Uhr, schrieb Dag-Erling Smørgrav d...@des.no:
Why is there a 0 after the 'i'? Because when you write abcdefghi, the
compiler actually stores abcdefghi\0. That's the definition of
string in C: a sequence of characters immediately followed by a 0. If
you don't want the 0
Matthias Andree matthias.and...@gmx.de writes:
Dag-Erling Smørgrav d...@des.no writes:
char a[9] = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i' };
char a[9] = abcdefghi;
suffices. The compiler knows there isn't room for the terminal '\0'
and omits it.
Some compilers (gcc at least) warn
On Thursday 25 February 2010 23:46:03 Dag-Erling Smørgrav wrote:
Matthias Andree matthias.and...@gmx.de writes:
Dag-Erling Smørgrav d...@des.no writes:
char a[9] = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i' };
char a[9] = abcdefghi;
suffices. The compiler knows there isn't room
Hi,
When I try allocated pointer to a pointer, and in it some pointers
(important: size is 2 bytes), the pointers lose their boundaries.
Why it can happen?
Test program in attach.
PS in freebsd 7, it's ok, in Linux too.
--
Andrey Zonov
alloc.c
Description: Binary data
On Wednesday 24 February 2010 14:44:35 Andrey Zonov wrote:
Hi,
When I try allocated pointer to a pointer, and in it some pointers
(important: size is 2 bytes), the pointers lose their boundaries.
Why it can happen?
Test program in attach.
Your test program is broken:
#define S1 ab
Andrey Zonov andrey.zo...@gmail.com writes:
When I try allocated pointer to a pointer, and in it some pointers
(important: size is 2 bytes), the pointers lose their boundaries.
Pointers have no boundareis in C.
PS in freebsd 7, it's ok, in Linux too.
Only by accident.
DES
--
Dag-Erling
And how free() finds that the need to release?
Dag-Erling Smørgrav пишет:
Andrey Zonov andrey.zo...@gmail.com writes:
When I try allocated pointer to a pointer, and in it some pointers
(important: size is 2 bytes), the pointers lose their boundaries.
Pointers have no boundareis in C.
Andrey Zonov andrey.zo...@gmail.com writes:
Dag-Erling Smørgrav d...@des.no writes:
Pointers have no boundareis in C.
And how free() finds that the need to release?
That is a very simple question with a very complicated answer. Whole
books have been written about the subject. Normally, I'd
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