let me know if it works
On Thu, Apr 2, 2009 at 1:54 PM, Robert Clayton wrote:
> Anthony,
>
> I did not want you to think I did not appreciate this addition. I just
> have not been able to grab a clean build yet to test yet. But when I
> grab a clean build I will test it.
>
> Bob
>
> 2009/3/30 A
Anthony,
I did not want you to think I did not appreciate this addition. I just
have not been able to grab a clean build yet to test yet. But when I
grab a clean build I will test it.
Bob
2009/3/30 Anthony Minessale :
> try this,
>
> go to latest trunk,
>
> set the terminators to both # and * "#
Anthony,
Thanks. Great idea. My fallback was to use * as a terminator and only
allow fixed size input. This is much better.
What do you know I just lost the hard drive on my test system. With my scripts.
I will reconstruct an begin soon
By the way I get an error in LUA on my windows build.
"error
try this,
go to latest trunk,
set the terminators to both # and * "#*" then when it stops check the
variable read_terminator_used to see if it was # or *
then you can continue in your loop
i added the channel var read_terminator_used which should contain
On Mon, Mar 30, 2009 at 10:42 AM, Robert
Anthony,
Yes and no. The original regex was a little more complex, it only got
simplified in the thread while trying to discover what was going
wrong.
Where we got "\\*|\\d{6}" to match either a "*" or "123456" the
original problem. It also allowed any entry if a single (or multiple)
asterisk were
how about leave the regex blank if you can't figure one out and just collect
6 digits and look for * yourself?
The one I told you saturday works for what you asked about. the one you
came back and asked about would require a | (or)
with 2 expressions.
On Mon, Mar 30, 2009 at 7:20 AM, Robert Clayt
Well, I hope that this thread has not died as it seems there has been
no solution.
Also, it seems there is not a solid understanding as to the
interaction between Lua and FS.
Does this suggest that I should abandon Lua for another scripting
implementation such as JavaScript?
2009/3/28 Anthony Min
Or to be more specific:
As a side note, when this gets worked out I am not sure if this answers my
other problem. If I wished for, say, "enter 6 numeric digits or an asterisk
to allow reentry." Is there any way to allow for an immediate response for
either 6 consecutive numeric digits or an aster
Anthony,
You are a good man. Early in the morning and up working.
Though not presenting an error these versions return no results.
agent_id = session:playAndGetDigits(1,6, 2, 1,"#",
"c:/DictationProject/audio/Validating.wav", "", "^([\d*]{6})$");
agent_id = session:playAndGetDigits(1,6, 2, 1
try
/^([\d*]{6})$/
\d is shorthand for 0-9 and anything in a [] is a set of chars so [\d*]
means 0-9 and *
[\d*]{6} means exactly 6 from the previous set and wrap the whole thing in
^$ means exact match
from beginning to end of the string.
2009/3/28 Robert Clayton
> Michael,
>
> Good start! W
Michael,
Good start! We are getting warmer.
Where "(\\*|\\d{6})" will not match either * or 123456 or anything I can
think of.
"\\*|\\d{6}" does match * and 123456 and does not match 1234
So far so good.
BUT, if an asterisk(s) are entered in a combination with numbers anything
goes **, *123, 123
2009/3/27 Robert Clayton :
> Michael,
>
> Also note the error message reprints the expression without the escape.
>
> Bob
>
> On Fri, Mar 27, 2009 at 2:29 PM, Michael Collins wrote:
That just hit me. Try "\\*" instead of "\*" to see if maybe the
backslash is getting dropped off between Lua and Fr
Michael,
Also note the error message reprints the expression without the escape.
Bob
On Fri, Mar 27, 2009 at 2:29 PM, Michael Collins wrote:
> 2009/3/27 Robert Clayton :
> > Michael,
> >
> > I liked "(\*|\d{6})" also but when entered in:
> >
> > agent_id = session:playAndGetDigits(1, 3, 2, 100
Michael,
Simple Working Reference:
agent_id = session:playAndGetDigits(1, 6, 2, 1,"#",
"c:/DictationProject/audio/Validating.wav", "", "23");
Entering 45 returned nothing as expected, entering 23 returned 23 as
expected.
2009/3/27 Robert Clayton :
> Michael,
>
> I liked "(\*|\d{6})" also but when entered in:
>
> agent_id = session:playAndGetDigits(1, 3, 2, 1,'#',
> 'c:/DictationProject/audio/Validating.wav', '', "(\*|\d{6})");
>
> Creates the error:
>
> 2009-03-27 14:05:36 [ERR] switch_regex.c:184 switch_regex_
Sorry the last line in my last email used a forward slash rather than a
backslash.
It should read:
The escape characters seem to disappear and FS attempts to use the, \* an
asterisk character, as * a metecharacter.
On Fri, Mar 27, 2009 at 2:02 PM, Michael Collins wrote:
> 2009/3/27 Robert Clay
Michael,
I liked "(\*|\d{6})" also but when entered in:
agent_id = session:playAndGetDigits(1, 3, 2, 1,'#',
'c:/DictationProject/audio/Validating.wav', '', "(\*|\d{6})");
Creates the error:
2009-03-27 14:05:36 [ERR] switch_regex.c:184 switch_regex_match_partial()
Regula
r Expression Error e
2009/3/27 Robert Clayton :
> As I understand it everything entered in square brackets(a character class)
> is literal. In parentheses it is read as a metacharacter.
Character classes have their own rules. I don't recommend using them
unless you know precisely what you are doing. I like Brian's reg
Brian,
Tried that as below.
agent_id = session:playAndGetDigits(1, 3, 2, 1,'#',
'c:/DictationProject/audio/Validating.wav', '', '(\*|\d{4})');
errors with:
2009-03-27 13:43:51 [ERR] switch_regex.c:184 switch_regex_match_partial()
Regular Expression Error expression[(*|d{4})] error[nothing t
As I understand it everything entered in square brackets(a character class)
is literal. In parentheses it is read as a metacharacter.
On Fri, Mar 27, 2009 at 2:48 AM, Even André Fiskvik wrote:
> Imho you always have to escape the asterisk character if that is what
> you want,
> so "[*]" is bad.
(\*|\d{6})
Here are my recommendations for reference:
http://www.amazon.com/Mastering-Regular-Expressions-Jeffrey-Friedl/dp/0596528124/ref=pd_bbs_sr_1?ie=UTF8&s=books&qid=1238166731&sr=8-1
This one is good too:
http://www.amazon.com/Regular-Expression-Pocket-Reference-Expressions/dp/059651427
in short? You basically repeated the exact same thing in the previous
email!
(\*|\d{4})
* or any 4 digit number you can change that if you like.
/b
On Mar 27, 2009, at 10:03 AM, Robert Clayton wrote:
>
> In short
Brian West
br...@freeswitch.org
-- Meet us a ClueCon! http://www.cluecon.c
Brian,
More succinctly how could I implement.
"Enter the six digit file number or press the asterisk key to restart and
enter again", assuming a person entered 3 digits got confused and wished to
enter the number again from the beginning?
Bob
2009/3/27 Brian West
> What exactly do you want to
Imho you always have to escape the asterisk character if that is what
you want,
so "[*]" is bad. You would want "[\*]".
See http://www.regular-expressions.info/characters.html for tips.
Best regards,
Even André
On 27. mars. 2009, at 05.05, Robert Clayton wrote:
> All,
>
> Ok I know it must
Brian,
Thanks for the rapid reply.
I was wanting, in Lua, for example to allow a user to enter either a file
number or an asterisk to abort the function and return to an earlier option.
I originally attempted this with a callback but found that at the end of the
recording the callback would retu
What exactly do you want to match? Can you give me examples?
/b
On Mar 26, 2009, at 11:05 PM, Robert Clayton wrote:
All,
Ok I know it must be me but...
In the Lua regex portion of session:playAndGetDigits what regex
would I use to match either a numeric entry, or an asterisk. It
seems w
All,
Ok I know it must be me but...
In the Lua regex portion of session:playAndGetDigits what regex would I use
to match either a numeric entry, or an asterisk. It seems when I attempt to
define an asterisk as a character rather than a metacharacter the regex
script is evaluated other than I woul
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