Yeah. A call to B and C eavesdrops call. I send dtmf for C to talk with B,
but B can't hear C. Here, what I had done in details:
[r...@centos4-4-vm ~]# telnet localhost 8021 Trying 127.0.0.1...
Connected to localhost.localdomain (127.0.0.1).
Escape character is '^]'.
Content-Type:
event socket, that should be better, its not on the
wiki, but
a session message with
eavesdrop-command header with data as the same as dtmf
should do the trick
Mike
On Oct 16, 2009, at 11:54 AM, Nikita Belov wrote:
Yes, it is what I need. But now I have problem with sending dtmf
-name: one of the applications
execute-app-arg: application data
/b
On Oct 19, 2009, at 11:42 AM, Nikita Belov wrote:
And what event name to use for sendevent command? Sorry for
importunity.
sendevent ???
Unique-ID: b9d6a35c-ee0c-4203-8d65-ed816e0a9c19
eavesdrop-command: 1
looked at the code to see what it would
take...
On Thu, Oct 15, 2009 at 3:16 AM, Nikita Belov nbe...@abisoft.spb.ru
wrote:
Thanks for answer.
As I've understood eavesdrop allows C to hear A and B, but A and B will
not
hear C. But in my case B SHOULD hear C. In my case A - client, B
call
Look at eavesdrop on the wiki.
JM
2009/10/14 Nikita Belov nbe...@abisoft.spb.ru
HI all,
I want to configure FS to make special conference call between three users
(A, B, C). In this conference C will hear A and B, but A will hear only B.
Can I make it using FS API commands? Does
