Hi Martin,
> The use of the QuadraticForm domain did not add any functionality to the
> CliffordAlgebra domain apart from enforcing the bilinear form to be symmetric.
> So is there reason why we would want to re-introduce it? its just more
> complexity and more overhead.
If you understood my m
On Monday 01 Feb 2010 14:42:55 Bertfried Fauser wrote:
> In term of Martin's Clifford package one can conclude:
> -- Clifford elements are given in a Grassmann basis
> -- There is a second Grassmann basis (dotted wedge) which allows to
> 'absorb' any antisymmetric
> part F.
> -- W.r.t. a Grassm
Dear Waldek,
> Vertex Normalordering as a Consequence of Nonsymmetric Bilinearforms
> in Clifford Algebras
>
> http://arxiv.org/pdf/hep-th/9504055
This is a bad source, it was one of my first papers on that subject
and there are by now much
better descriptions, eg:
arXiv:math-ph/0212032 and arX
Bertfried Fauser wrote:
> I am currently totally absorbed with other things and will most likely
> not have much
> (any) time to look in detail into the code. What kind of thing was
> that what you did not
> understand about the paper (which paper by the way)? Perhaps I can at
> least explain
> wha
Dear Waldek and Martin,
I am currently totally absorbed with other things and will most likely
not have much
(any) time to look in detail into the code. What kind of thing was
that what you did not
understand about the paper (which paper by the way)? Perhaps I can at
least explain
what the differe
