Hi,
In the old references there is a function "build" that is used for
building tree nodes. Using this function one can build a conditional
expression as follows:
build(EQ_EXPR, integet_type_node, left, rith);
which is left == right
But, as I noticed this function "build" is not maintained (use
On 1/23/07, Ferad Zyulkyarov <[EMAIL PROTECTED]> wrote:
But, as I noticed this function "build" is not maintained (used) by
gcc any more. Instead build, what else may I use to create a
conditional expression node?
Look for buildN where N is a small integer ;-)
I think you want build2 for EQ_EX
Thanks a lot, that's it
On 1/23/07, Steven Bosscher <[EMAIL PROTECTED]> wrote:
On 1/23/07, Ferad Zyulkyarov <[EMAIL PROTECTED]> wrote:
> But, as I noticed this function "build" is not maintained (used) by
> gcc any more. Instead build, what else may I use to create a
> conditional expression nod
> "Ferad" == Ferad Zyulkyarov <[EMAIL PROTECTED]> writes:
Ferad> build(EQ_EXPR, integet_type_node, left, rith);
Ferad> which is left == right
Ferad> But, as I noticed this function "build" is not maintained (used) by
Ferad> gcc any more. Instead build, what else may I use to create a
Ferad> c
Hi,
I've noticed that you've asked a few questions about trees on the
list. You might want to read a tutorial on trees in GCC; there are a
few kicking around out there.
Sure I would like to look at any tutorial. I found some, but most of
them were not complete :( I would appreciate if you can
