Arthur Schwarz writes:
> # include
> # include
>
> using namespace std;
>
> ifstream x;
> ifstream& y = x;
>
> int main(int argc, char** argv) {
> y = x;
> return 0;
> }
>
> g++.3.4.4 output
> m1.cpp: In member function `std::basic_ios >&
> std::basic_ios >::operator=(const
> std::basic_
Arthur Schwarz wrote:
> /*
> * m3.cpp
> */
>
> # include
> # include
>
> using namespace std;
>
> ifstream x;
> ifstream y();
> If 'std::ifstream' not found, why is 'std::ifstream y();' legal?
Ooh, I know this one. It's because it's not a definition of an ifstream
object constructed
In light of the foolhardy commitment I made, here are some reprehensible
diagnostic messages and the superb recanting of the obvious. As always, the
messaging and comments are gratuitously provided and I hope accepted in the
same manner.
Two notes (made before):
1: Some messages are needlessl
