[Bug c++/28169] Tertiary operator: object creation and initialization

2006-10-11 Thread bangerth at dealii dot org
--- Comment #5 from bangerth at dealii dot org 2006-10-12 01:50 --- gcc is correct. It is true that the result of the ?: operator is a reference to the Base object of the Derived object created in the second arm. However, the result is an rvalue, and a constant reference is initialized w

[Bug c++/28169] Tertiary operator: object creation and initialization

2006-06-26 Thread pinskia at gcc dot gnu dot org
--- Comment #1 from pinskia at gcc dot gnu dot org 2006-06-26 18:16 --- Here is what is happening currently with GCC: Base ctor... Derived ctor... Base copy ctor... ~Derived called... ~Base called... Base show called... ~Base called... So you missed the copy constructor, now I don't kno

[Bug c++/28169] Tertiary operator: object creation and initialization

2006-06-26 Thread pinskia at gcc dot gnu dot org
--- Comment #2 from pinskia at gcc dot gnu dot org 2006-06-26 18:18 --- Note ICC produces: Base ctor... Derived ctor... ~Derived called... ~Base called... Base show called... which might be just as bad. -- http://gcc.gnu.org/bugzilla/show_bug.cgi?id=28169

[Bug c++/28169] Tertiary operator: object creation and initialization

2006-06-26 Thread joseph dot rajesh at gmail dot com
--- Comment #3 from joseph dot rajesh at gmail dot com 2006-06-27 04:09 --- No I haven't missed the copy constructor... I checked the working with copy constructor also... I know g++ is doing a conversion and making a copy of type "Base" (Using Base copy constructor)... that's why the

[Bug c++/28169] Tertiary operator: object creation and initialization

2006-06-27 Thread joseph dot rajesh at gmail dot com
--- Comment #4 from joseph dot rajesh at gmail dot com 2006-06-27 07:38 --- The intel compiler version 9.1 gave me the following output Base ctor... Derived ctor... Base COPTY ctor... Base COPTY ctor... ~Base called... ~Derived called... ~Base called... Base show called... ~Base called