The specialization of a function is not called if compile with -03 option,
the generic implementation is called insteed.
This appear only if the declaration of the specialization is in another
file.
The specialization is called if compiled with -02 or lees optimization, or
if the generic implementation is declared with the buildin noinline.
Configuration of gcc -v:
Using built-in specs.
Target: i686-pc-linux-gnu
Configured with: ../src/configure
--prefix=/project/spg/tools/Open-Sources/gcc/4.1.1/Linux-x86/
--enable-__cxa_atexit --enable-shared --enable-long-long --enable-threads
--enable-languages=c,c++ --with-gnu-as --with-gnu-ar --with-gnu-ld --with-gcc
Thread model: posix
gcc version 4.1.1
Three files:
header
#ifndef _TCLASS_H_
#define _TCLASS_H_
template<typename T> bool foo(T val)
{
return false;
}
#endif
scpecialization:
#include "tclass.h"
template<> bool foo(int val)
{
return true;
}
main:
#include "tclass.h"
int main() {
return(foo(1));
}
--
Summary: Specialization of a function is not called if compile
with -03 option
Product: gcc
Version: 4.1.1
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: maxime dot fiandino at imag dot fr
GCC build triplet: i686-pc-linux-gnu
GCC host triplet: i686-pc-linux-gnu
GCC target triplet: i686-pc-linux-gnu
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=28271
