The following program fails to compile:
template <typename T> struct A {};
template <typename T> struct B
{
typedef T type;
operator A<T>() const;
};
template <typename T> void F(const A<typename B<T>::type> &) {}
template <typename T> B<T>::operator A<T>() const {}
test.cpp:8: error: no 'B<T>::operator A<typename B<T>::type>() const' member
fun
ction declared in class 'B<T>'
test.cpp:8: error: template definition of non-template 'B<T>::operator
A<typenam
e B<T>::type>() const'
If you define the cast operator before F, the error goes away. A similar issue
was previously filed under bug #8578 and marked as fixed in gcc 3.3.
--
Summary: Cast typename operator
Product: gcc
Version: 4.1.1
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: spam at david dot osborn dot name
GCC build triplet: i686-pc-mingw32
GCC host triplet: i686-pc-mingw32
GCC target triplet: i686-pc-mingw32
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=30169
