[Bug c++/38007] New: g++ instantiate same operator twice due to bitfield in -O0 mode, causing symbol already defined assembler error

[jengliang at gmail dot com]

Following code produces symbol already defined assembler error when compiled
with g++ 4.2.4 with -O0 flag.  It can compile without problem with g++ 4.1.1.

=== foo.hpp ===
class foo {
    public:
        template <typename T> operator T ();
};

template <typename T>
    inline foo::operator T () {
        return (T)0;
    }

=== foo.cpp ===
#include "foo.hpp"

struct bar {
    unsigned int _bar : 24;
};

int main() {
    foo a;
    unsigned int b = a;
    bar c;
    c._bar = a;
    return 1;
}

====
compile with g++ -O0 foo.cpp

Regards,
Jeng-Liang


-- 
           Summary: g++ instantiate same operator twice due to bitfield in -
                    O0 mode, causing symbol already defined assembler error
           Product: gcc
           Version: 4.2.4
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: jengliang at gmail dot com


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=38007