[Bug c++/46264] New: Trunk [4.6.0 20101028] - An overloaded operator returning rvalue reference invalidates stack.

[mirza.husadzic at gmail dot com]

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=46264

           Summary: Trunk [4.6.0 20101028] - An overloaded operator
                    returning rvalue reference invalidates stack.
           Product: gcc
           Version: unknown
            Status: UNCONFIRMED
          Severity: major
          Priority: P3
         Component: c++
        AssignedTo: unassig...@gcc.gnu.org
        ReportedBy: mirza.husad...@gmail.com


Created attachment 22223
  --> http://gcc.gnu.org/bugzilla/attachment.cgi?id=22223
./dist/bin/g++ -v -std=c++0x -Wall -g -save-temps rvalue_bug.cpp

The following code is compiled ('-std=c++0x -Wall -g') without optimizations.

Sounds bizarre but the for loop (operator*) invalidates the stack, where
invalid data pointer goes to delete (at the destructor) causing segmentation
fault in libc.so. 
If the code is compiled without *for loop* there is no bug.

Note: By compiling with optimization flags (-0, -O1, -O2, -O3) the bug can't
be reproduced.


#include <iostream>

using namespace std;

class foo
{
        float *data;
        bool   reused;

 public:

        foo() : data(new float), reused(false) 
        {
                cout << "Allocating data: " << data << endl;
        }

        foo(foo&& f) : data(move(f.data)), reused(false) 
        {
                f.data = NULL;
                cout << "Move constructor." << endl;
        }

        ~foo()
        {
                if(reused == false)
                { 
                        cout << "Deleting data: " << data << endl;
                        delete data;
                }else
                        cout << "Reused data: " << data << endl;
        }

        foo&& operator*(const foo& b) const
        {
                foo ab;

                int sum = 0;

                /// This for loop causes invalidation of stack.
                for(int i=0; i<0; i++)
                        sum += i;         

                ab.reused = true;

                cout << "Operator *. Sum: " << sum << endl;

                return move(ab);
        }
};


int
main()
{
        foo a;
        foo b;

        foo c = a * b;

        return 0;
}