Using r153474 with LTO, the compilation units below appear to be improperly
turned into a terminating executable.
reg...@john-home:~$ current-gcc -g -Wall -O3 -flto -c rnd_output0.c
reg...@john-home:~$ current-gcc -g -Wall -O3 -flto -c rnd_output1.c
reg...@john-home:~$ current-gcc -g -Wall -O3 -flto rnd_output1.o rnd_output0.o
-o rand
reg...@john-home:~$ ./rand
Done
reg...@john-home:~$
reg...@john-home:~$ cat rnd_output0.c
#include <assert.h>
#include <stdio.h>
int func_5();
int i = 0;
int func_2()
{
func_5();
assert(i == 0);
assert(i == 0);
assert(i == 0);
assert(i == 0);
assert(i == 0);
assert(i == 0);
assert(i == 0);
return 0;
}
int func_1(int p)
{
func_2();
return 0;
}
int main(void)
{
func_1(func_2());
printf ("Done\n");
return 0;
}
reg...@john-home:~$ cat rnd_output1.c
int func_5()
{
while(1)
;
return 0;
}
--
Summary: possible LTO termination bug
Product: gcc
Version: unknown
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: regehr at cs dot utah dot edu
GCC build triplet: i686-pc-linux-gnu
GCC host triplet: i686-pc-linux-gnu
GCC target triplet: i686-pc-linux-gnu
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=41805
