https://gcc.gnu.org/bugzilla/show_bug.cgi?id=90219
Bug ID: 90219
Summary: Wrong source location for "cannot convert to a pointer
type" warning
Product: gcc
Version: 8.3.1
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c
Assignee: unassigned at gcc dot gnu.org
Reporter: tbaeder at redhat dot com
Target Milestone: ---
Using gcc 8.3.1 and the following sample code:
static int use_float(float *f) {
return (int)*f;
}
// Type your code here, or load an example.
int square(int num) {
float f = 1.0f;
return use_float((float*)f);
}
it prints the following error:
<source>: In function 'square':
<source>:8:5: error: cannot convert to a pointer type
return use_float((float*)f);
^~~~~~
which is highlighting the wrong part of that line. The error message itself
could be improved as well (I forgot to take the address of f of course!) but I
think the cast should be highlighted.
If use_float() is instead called stand-alone and not as part of the return
statment:
int square(int num) {
float f = 1.0f;
use_float((float*)f);
return 1;
}
The source location is slightly better:
<source>: In function 'square':
<source>:8:5: error: cannot convert to a pointer type
use_float((float*)f);
^~~~~~~~~
