https://gcc.gnu.org/bugzilla/show_bug.cgi?id=82898
Martin Sebor changed:
What|Removed |Added
Status|UNCONFIRMED |RESOLVED
See Also|
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=82898
Martin Sebor changed:
What|Removed |Added
CC||msebor at gcc dot gnu.org
--- Comment #5
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=82898
--- Comment #4 from rguenther at suse dot de ---
On Wed, 8 Nov 2017, antoshkka at gmail dot com wrote:
> https://gcc.gnu.org/bugzilla/show_bug.cgi?id=82898
>
> --- Comment #3 from Antony Polukhin ---
> > At least in the gcc model, the type of
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=82898
--- Comment #3 from Antony Polukhin ---
> At least in the gcc model, the type of a pointer is meaningless
> as long as you do not dereference it using that type<...>
OK, does dereferencing the pointers change anything?
void foo(int* i, const
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=82898
Richard Biener changed:
What|Removed |Added
Keywords||alias, missed-optimization
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=82898
--- Comment #1 from Marc Glisse ---
At least in the gcc model, the type of a pointer is meaningless as long as you
do not dereference it using that type, so I am not sure what can be done here.