--- Comment #1 from pinskia at gcc dot gnu dot org 2008-03-16 22:46 ---
Yes and GCC behavior is correct. pasting foo and ( don't make a valid
preprocessing token.
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pinskia at gcc dot gnu dot org changed:
What|Removed |Added
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--- Comment #2 from pinskia at gcc dot gnu dot org 2008-03-16 22:49 ---
## only works to form a valid token, if it does not, then the code is invalid.
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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=35610
--- Comment #3 from andry at inbox dot ru 2008-03-16 22:56 ---
(In reply to comment #2)
> ## only works to form a valid token, if it does not, then the code is invalid.
>
When i can understand which token is valid then?
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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=35610
--- Comment #4 from pinskia at gcc dot gnu dot org 2008-03-16 23:06 ---
(In reply to comment #3)
> When i can understand which token is valid then?
By reading the C/C++ standards :). But basically in this case foo and ( are
two different tokens. Examples of valid tokens: "->", "foo",
