If two arrays do not have the exact same element type including qualification,
this could be e.g. f(int (&&)[]) vs. f(int const (&)[]), which can still be
distinguished by the lvalue-rvalue tiebreaker.
By tightening this branch (in accordance with the letter of the Standard) we
fall through to
On 4/18/22 18:09, Ed Catmur wrote:
If two arrays do not have the exact same element type including qualification, this could
be e.g. f(int (&&)[]) vs. f(int const (&)[]), which can still be distinguished
by the lvalue-rvalue tiebreaker.
By tightening this branch (in accordance with the letter
