The cts:triples() call is de-duplicating triples as it brings them back
to the E-node. Other methods are faster because they avoid the
de-duplication and can therefore often perform operations on D-nodes
rather than centrally on the E-node.
We hope to add a function that estimates the count of
HI Anthony.
Thanks for the feedback. It is possible, but unlikely, that I
have 14% difference. Keep in mind, the 14% difference is not with
fn:count(cts:triples()) vs counting sem:triple because
fn:count(cts:triples()) never finishes for me.
Classification: For internal use only
David, are all of your triples unique? A SPARQL-type count of triples
(which should include cts:triples) would only return the number of unique
triples, whereas a CTS search on sem:triple would include redundant
triples in the count (I would assume). I'm
