Does anyone know how to go about escaping a * in a bash script?
I want to do the following
query= select * from table where column1='something'
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Ow Mun Heng wrote:
Does anyone know how to go about escaping a * in a bash script?
I want to do the following
query= select * from table where column1='something'
As you use the it is still a * in the $query, but you have to be
On Sun, 2006-10-08 at 18:13 +0800, Ow Mun Heng wrote:
Does anyone know how to go about escaping a * in a bash script?
I want to do the following
query= select * from table where column1='something'
nevermind..
I did it like this
query= select \ *\ from table where
On 08/10/06, Ow Mun Heng [EMAIL PROTECTED] wrote:
Does anyone know how to go about escaping a * in a bash script?
I want to do the following
query= select * from table where column1='something'
Well one you can use different quotes:
query='select * from table'
Or you can \* it.
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