Is there a way to check out a tree without changing the mtime of any
files that you have already checked out and which are the same as the
version you are checking out? It seems that checkout-cache -a doesn't
overwrite any existing files, and checkout-cache -f -a overwrites all
files and gives
* David Woodhouse [EMAIL PROTECTED] wrote:
On Tue, 2005-04-19 at 23:00 +1000, Paul Mackerras wrote:
Is there a way to check out a tree without changing the mtime of any
files that you have already checked out and which are the same as the
version you are checking out? It seems that
On Tue, 19 Apr 2005, Petr Baudis wrote:
I'd actually prefer, if:
(i) checkout-cache simply wouldn't touch files whose stat matches with
what is in the cache; it updates the cache with the stat informations
of touched files
Run update-cache --refresh _before_ doing the checkout-cache,
On Tue, 19 Apr 2005, Linus Torvalds wrote:
The real expense right now of a merge is that we always forget all the
stat information when we do a merge (since it does a read-tree). I have a
cunning way to fix that, though, which is to make read-tree -m read in
the old index state like it
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