> HsParser does not allow method declarations to follow a default > implementation of a method. > > class G a where > f :: a -> a > f x = x > g :: a -> a > > Optional semicolons or empty statements are not permitted in > do-expressions. > > f x = do ;; x ; > > That is probably the reason why this example fails to parse too: > > f x = do > y > where y = x
Thanks, both fixed. Cheers, Simon _______________________________________________ Glasgow-haskell-bugs mailing list [EMAIL PROTECTED] http://www.haskell.org/mailman/listinfo/glasgow-haskell-bugs