Simon Marlow ([EMAIL PROTECTED]) wrote:
Hi Simon!
> I've put up an x86_64/Linux registerised build for testing here:
Thank you very much.
> This is a binary distribution: ./configure && make -k install. The -k
> is necessary because it doesn't have all the docs. It was built on
> Fedora FC3.
The User's Guide says:
The only thing that differs between operators in types and
operators in expressions is that ordinary non-constructor
operators, such as + and * are not allowed in types. Reason:
the uniform thing to do would be to make them type variables,
On 08 March 2005 15:59, Duncan Coutts wrote:
> On Tue, 2005-03-08 at 15:16 +, Simon Marlow wrote:
>> I've put up an x86_64/Linux registerised build for testing here:
>>
>>
>>
http://www.haskell.org/ghc/dist/stable/dist/ghc-6.4-x86_64-unknown-linux
>> .tar.bz2
>>
>> This is a binary distrib
On Tue, 2005-03-08 at 15:16 +, Simon Marlow wrote:
> I've put up an x86_64/Linux registerised build for testing here:
>
>
> http://www.haskell.org/ghc/dist/stable/dist/ghc-6.4-x86_64-unknown-linux
> .tar.bz2
>
> This is a binary distribution: ./configure && make -k install. The -k
> is nec
Hi folks,
having set up some monadic type for usage with Happy, I've encountered
some thing that puzzles me: as it seems, once happyError gets called, you
cannot get back into the parser "loop" even if you return some `Failed
xy::ParseMonad' instead of calling error. How and where do I catch such
I've put up an x86_64/Linux registerised build for testing here:
http://www.haskell.org/ghc/dist/stable/dist/ghc-6.4-x86_64-unknown-linux
.tar.bz2
This is a binary distribution: ./configure && make -k install. The -k
is necessary because it doesn't have all the docs. It was built on
Fedora F
On 07 March 2005 18:01, Kurt Roeckx wrote:
> On Mon, Mar 07, 2005 at 11:47:31AM -, Simon Marlow wrote:
>>
>> $ cat bug.c
>> register void * R1 __asm__("%r13");
>>
>> extern void g(void);
>> static void f(void) {
>> R1 = g;
>> goto *R1;
>> }
>> $ gcc -S -O bug.c
>> $
>>
>> And take a look
Wolfgang Thaller wrote:
I've uploaded a Mac OS X installer based on the stable tree from March
2nd + the patches I committed yesterday at:
http://opeongo.cas.mcmaster.ca/~wolfgang/GHC-6.4.20050302.pkg.zip
I've only a remote account on a Mac. Do I have a chance to install
ghc-6.4 locally as a non
On 05/03/2005, at 4:26 AM, Wolfgang Thaller wrote:
I've uploaded a Mac OS X installer based on the stable tree from
March
2nd + the patches I committed yesterday at:
http://opeongo.cas.mcmaster.ca/~wolfgang/GHC-6.4.20050302.pkg.zip
A quick fix:
sudo sh fix_install_names.sh /usr/local/lib/ghc-6.4
Feature Requests item #1124080, was opened at 2005-02-16 17:01
Message generated for change (Comment added) made by simonmar
You can respond by visiting:
https://sourceforge.net/tracker/?func=detail&atid=358032&aid=1124080&group_id=8032
Category: None
Group: None
Status: Open
>Priority: 3
Submitt
[redirecting to GHC users list]
John is right. I've added something to the user manual to say so.
| -Original Message-
| From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of John Meacham
| Sent: 08 March 2005 00:20
| To: haskell@haskell.org
| Subject: Re: [Haskell] "Classic" vs
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