On Tue, 2005-12-13 at 09:47 +1100, Donald Bruce Stewart wrote:
> Most distros are using binary bootstrapping. I think OpenBSD is the only
> one building from .hc src.
That's because none of the rest of us had heard that it'd been fixed!
I'm glad to hear it, we might switch. Gentoo users ought to
duncan.coutts:
> On Mon, 2005-12-12 at 18:20 +, Andrew Walrond wrote:
> > I run a source based linux distro called Heretix, and I want to make a ghc
> > package which will install with or without an existing ghc. At the moment,
> > we
> > supply a binary-ghc package, whch is a prerequisite o
andrew:
> I run a source based linux distro called Heretix, and I want to make a ghc
> package which will install with or without an existing ghc. At the moment, we
> supply a binary-ghc package, whch is a prerequisite of the from-source ghc
> package.
>
> It seems to me that I can prepare HC t
fwiw: I have not yet used .ghci files - even though I try to use
"ghc --make" instead of full-blown makefiles, I tend to write
mini-makefiles that set up paths, options, etc, before calling
"ghc --make" to do the real work (well sometimes, there's some
non-Haskell work to be done first). And if yo
That made it work, thanks.
Frederik
On Mon, Dec 12, 2005 at 07:01:42PM -, Simon Marlow wrote:
> On 12 December 2005 18:49, Frederik Eaton wrote:
>
> > $ ghc -pgml gcc -pgmP "gcc -E -undef -traditional" -pgmc gcc --make
> > Matrix.hs -o matrix Chasing modules from: Matrix.hs
> > [1 of 2] Comp
On Mon, Dec 12, 2005 at 03:38:18PM -, Simon Peyton-Jones wrote:
> Interesting example. Yes, GHC builds recursive dictionaries these days.
> There's a bit of discussion in our SYB paper in ICFP'05.
> http://research.microsoft.com/%7Esimonpj/papers/hmap/ And Martin
> Sulzmann has a whole
Hello,
I have been using the .ghci file with GHCi to set global options for
my project and I find it very useful. The kind of options I put there
are: where to put .hi/.o files, what warnings to produce, where to
look for code. etc. It works great. I was thinking that it would be
very convenient
On Mon, 2005-12-12 at 18:20 +, Andrew Walrond wrote:
> I run a source based linux distro called Heretix, and I want to make a ghc
> package which will install with or without an existing ghc. At the moment, we
> supply a binary-ghc package, whch is a prerequisite of the from-source ghc
> pac
On 12 December 2005 18:49, Frederik Eaton wrote:
> $ ghc -pgml gcc -pgmP "gcc -E -undef -traditional" -pgmc gcc --make
> Matrix.hs -o matrix Chasing modules from: Matrix.hs
> [1 of 2] Compiling Fu.Prepose ( Fu/Prepose.hs, Fu/Prepose.o )
> ghc-6.5.20051208: could not execute: gcc-3.4.3
>
> M
$ ghc -pgml gcc -pgmP "gcc -E -undef -traditional" -pgmc gcc --make Matrix.hs
-o matrix
Chasing modules from: Matrix.hs
[1 of 2] Compiling Fu.Prepose ( Fu/Prepose.hs, Fu/Prepose.o )
ghc-6.5.20051208: could not execute: gcc-3.4.3
Maybe a more informative error message would be a useful featu
I run a source based linux distro called Heretix, and I want to make a ghc
package which will install with or without an existing ghc. At the moment, we
supply a binary-ghc package, whch is a prerequisite of the from-source ghc
package.
It seems to me that I can prepare HC tarballs for my targe
Interesting example. Yes, GHC builds recursive dictionaries these days.
There's a bit of discussion in our SYB paper in ICFP'05.
http://research.microsoft.com/%7Esimonpj/papers/hmap/ And Martin
Sulzmann has a whole paper about this point.
http://www.comp.nus.edu.sg/~sulzmann/ ("Co-induction..."
On 10 December 2005 05:08, Frederik Eaton wrote:
> $ ghc -pgmc gcc --make Matrix.hs -o matrix
> Chasing modules from: Matrix.hs
> [1 of 2] Compiling Fu.Prepose ( Fu/Prepose.hs, Fu/Prepose.o )
> ghc-6.5.20051208: could not execute: gcc-3.4.3
>
> Hard-coding things is ... not ... nice ...
Yo
I'm puzzled that the following is accepted. Is some sort of greatest
fixed point computation used for instances?
{-# OPTIONS_GHC -fglasgow-exts #-}
module M where
class C a b where c :: a -> b -> Bool
instance C b b => C (Maybe a) b where c x y = c y y
f :: Maybe a -> Bool
f x = c x x
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