INLINE:
- no effect for a recursive function
- for a non-recursive function, always inline a call that
(a) is applied to as many args as the LHS of the defn
(b) has some interesting context. Ie (\y x- f x y) doesn't
inline f
INLINEABLE
a) For type-class
On Thu, Jun 9, 2011 at 1:43 PM, Simon Peyton-Jones
simo...@microsoft.com wrote:
Does that help?
Definitely. Thanks!
Johan
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Hi,
I'm trying to write a test case to make sure memset gets unrolled
correctly by the backend. Unrolling only happens when the alignment
and size is statically known so writing a simple Cmm loop that calls
memset won't work as the sizes won't be statically known. I want to
test memset with a
Great, thanks. I've added that link to the user-documentation page for the GHC
API, here
http://haskell.org/haskellwiki/GHC/As_a_library#Links
Please do elaborate that page, which is a bit thin at the moment. It should be
easier to find supporting info about the GHC API.
Simon
|
On 09/06/2011 12:43, Simon Peyton-Jones wrote:
INLINE:
- no effect for a recursive function
- for a non-recursive function, always inline a call that
(a) is applied to as many args as the LHS of the defn
(b) has some interesting context. Ie (\y x- f x y) doesn't
Hello,
On Thu, Jun 09, 2011 at 03:44:43PM +0200, Johan Tibell wrote:
...
I initially
tried to use the CPP ## string concatenation operator to create unique
names (tedious, but works) but GHC runs CPP in traditional mode so
that doesn't work.
One -traditional way that I have used to
[Ian, sorry for the duplicate — wrong sender email at first.]
Ian Lynagh:
On Mon, Jun 06, 2011 at 03:47:57PM +0100, Malcolm Wallace wrote:
On 6 Jun 2011, at 13:49, Lyndon Maydwell wrote:
I would be fantastic if XCode wasn't a dependency. ...
Not to detract at all from the work of the
