> package main
>
> func fi(i int) {}
> func fis(is []int) {}
>
> type TI int
> type TIS []int
>
> func main() {
> var ti TI
> fi(ti) // cannot use ti (type TI) as type int in argument to fi
>
> var tis TIS
> fis(tis) // no problems!
> }
>
>
--
You received this message bec
You've run into the distinction between named types and unnamed types:
https://golang.org/ref/spec#Properties_of_types_and_values
int, TI, and TIS are named types. []int is an unnamed type. The rules for
assignability say:
> A value x is assignable to a variable of type T ("x is assignable to T")
This is actually a really good question. To the spec-mobile!
https://golang.org/ref/spec#Calls
Except for one special case, arguments must be single-valued expressions
> assignable to the parameter types of F and are evaluated before the
> function is called.
Okay, so the arguments must be assi
I had written a response, but was beaten to the punch by Steven and Alex by
seconds.
I'll just add to what they've said. A surprising fact is that `int` is
actually not an unnamed type, it's a pre-declared identifier:
https://golang.org/ref/spec#Predeclared_identifiers
Here's the (seemingly taut
