Wow Thank you Don
you have a very keen eye.
On Wed, Oct 27, 2010 at 12:53 AM, l.denardo lorenzo.dena...@gmail.comwrote:
I need a good pair of glasses :-)
On Oct 26, 5:42 pm, Don Schwarz schwa...@google.com wrote:
Yes, it's a bug in your code:
while(tempFlag == true);
Note the
Don't know APIs very well, but anyway it looks like in the while
version you check one link in the condition, then request newLink
again in the method body. At the end of the list you check for the
last element not to be null, then ask for one more (which is out of
list bounds).
You should be
Sorry to use specific sample code. So I tried more basic following code.
try
{
int i =0;
boolean tempFlag = false;
while(tempFlag == true);
{
i++;
out.println(tempFlag + i + := + tempFlag);
tempFlag = false;
}
}
catch(Exception e)
{
out.println(Error + e.toString());
}
Really looks like a bug. Test condition should fail without printing
anything, in fact.
Sorry for my misleading answer, and thanks for sharing this.
Lorenzo
On Oct 26, 5:22 pm, doc123 doc.u...@gmail.com wrote:
Sorry to use specific sample code. So I tried more basic following code.
try
{
Yes, it's a bug in your code:
while(tempFlag == true);
Note the semicolon. Try removing it.
On Tue, Oct 26, 2010 at 10:22 AM, doc123 doc.u...@gmail.com wrote:
Sorry to use specific sample code. So I tried more basic following code.
try
{
int i =0;
boolean tempFlag = false;
I need a good pair of glasses :-)
On Oct 26, 5:42 pm, Don Schwarz schwa...@google.com wrote:
Yes, it's a bug in your code:
while(tempFlag == true);
Note the semicolon. Try removing it.
On Tue, Oct 26, 2010 at 10:22 AM, doc123 doc.u...@gmail.com wrote:
Sorry to use specific sample code.
