You forget to check one case.
you can choose to pick an entire range by placing two tickets at the end.

For example,
if someone else picked 10 and 30
you can pick 11 and 29 and take the entire interval [11, 29]

Check out this code <https://ideone.com/QPu9pB> from line 49 to 54

在2021年5月3日星期一 UTC-7 上午7:04:57<sudeep.c...@gmail.com> 写道:

> Can someone please help me with what is wrong with my solution?
> The idea is to either pick a interval from start till the first smallest 
> value (suppose if smallest is 3, then we can have win for 1 and 2 by 
> picking 2), largest value to K (suppose if largest is 7 and k is 10, then 
> we can have win for 8,9 and 10 by picking 8) as well as other possibilites 
> which will be in between intervals (like [3, 7]--> pick 4, then win for 
> 4,5). 
>
> import java.io.BufferedReader;
> import java.io.IOException;
> import java.io.InputStreamReader;
> import java.io.PrintWriter;
> import java.util.ArrayList;
> import java.util.Arrays;
> import java.util.Collections;
> import java.util.List;
>
> public class Solution {
> public static void main(String[] args) throws IOException {
> BufferedReader br = new BufferedReader(
> new InputStreamReader(System.in));
> int t = Integer.parseInt(br.readLine());
> PrintWriter out = new PrintWriter(System.out);
> StringBuilder str = new StringBuilder("");
> for(int h=1;h<=t;h++)
> {
> str.append("Case #"+h+": ");
> String[] in = br.readLine().trim().split(" ");
> int n = Integer.parseInt(in[0]);
> long k = Long.parseLong(in[1]);
> long arr[] = new long[n];
> in = br.readLine().trim().split(" ");
> for(int i=0;i<n;i++){
> arr[i]=Long.parseLong(in[i]);
> }
> List<Long> diff = new ArrayList<>();
> Arrays.sort(arr);
> for(int i=1;i<arr.length;i++){
> long d = arr[i]-arr[i-1];
> if(d>0){
> d--;
> }
> diff.add(d);
> }
> Double p = new Double(0);
> Collections.sort(diff);
>
> List<Long> ans = new ArrayList<>();
> ans.add(k - arr[n-1]);
> ans.add(arr[0]-1);
> for(int j = diff.size()-1;j>=Math.max(0, diff.size()-2);j--){
> ans.add((diff.get(j)+1) / 2);
> }
> Collections.sort(ans);
> p += ans.get(ans.size()-1);
> p+=ans.get(ans.size()-2);
> str.append(p/(double)k+"\n");
> }
> out.print(str);
> out.flush();
> br.close();
> }
> }
>

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