* Moritz Lennert [2018-08-23 13:02:03 +0200]:
On 23/08/18 11:52, Nikos Alexandris wrote:
* Stefan Blumentrath [2018-08-23 07:23:12 +]:
Dear Nikos,
Can you give us a bit more context? What is it you want to achieve?
How are you using r.stats and what is it you want to do with the
outpu
On 23/08/18 11:52, Nikos Alexandris wrote:
* Stefan Blumentrath [2018-08-23 07:23:12 +]:
Dear Nikos,
Can you give us a bit more context? What is it you want to achieve?
How are you using r.stats and what is it you want to do with the
output?
Personally, I am not too familiar with perfor
* Stefan Blumentrath [2018-08-23 07:23:12 +]:
Dear Nikos,
Can you give us a bit more context? What is it you want to achieve?
How are you using r.stats and what is it you want to do with the
output?
Personally, I am not too familiar with performance implications of
NumPy vs. plain Python
/table operations
(avoiding pandas)...
Cheers
Stefan
-Original Message-
From: Nikos Alexandris
Sent: onsdag 22. august 2018 17:57
To: Stefan Blumentrath
Cc: GRASS-GIS development mailing list
Subject: Re: [GRASS-dev] Parsing output of r.category which includes labels
Stefan,
a somewhat
Stefan,
a somewhat irrelevant question to the original subject:
do you think the NumPy way is worth to collage a series of `r.stats`
outputs?
Imagine administrative boundaries and one `r.stats` call for each. They
may be tenths, or hundreds, or thousands as the script is meant to cover
European
* Moritz Lennert [2018-08-21 12:57:01 +0200]:
On 21/08/18 12:47, Stefan Blumentrath wrote:
Hi Nikos,
If you are interested in dictionary output you could do:
category_labels = grass.parse_command('r.category', map='youmap',
delimiter='\t')
Right, nice solution !
For those not very famili
On 21/08/18 12:47, Stefan Blumentrath wrote:
Hi Nikos,
If you are interested in dictionary output you could do:
category_labels = grass.parse_command('r.category', map='youmap',
delimiter='\t')
Right, nice solution !
For those not very familiar with the scripting library: the "delimiter"
o
2018 02:02
To: Moritz Lennert
Cc: GRASS-GIS development mailing list
Subject: Re: [GRASS-dev] Parsing output of r.category which includes labels
* Moritz Lennert [2018-08-20 13:40:36 +0200]:
>On 19/08/18 22:19, Nikos Alexandris wrote:
>>If I am not wrong, all use cases of `read_comman
* Stefan Blumentrath [2018-08-20 10:48:34 +]:
Hi Nikos,
You could use numpy and genfromtxt() to parse the output string...
genfromtxt() requires an StringIO object (or file) and StringIO (from io)
requires unicode()...
So you could do:
from io import StringIO
import numpy as np
output =
* Moritz Lennert [2018-08-20 13:40:36 +0200]:
On 19/08/18 22:19, Nikos Alexandris wrote:
If I am not wrong, all use cases of `read_command()` [0, 1],
in (at least) the grass-addons repository, do not consider an output
from `r.category` which includes labels.
[0]
https://grass.osgeo.org/gras
On 19/08/18 22:19, Nikos Alexandris wrote:
If I am not wrong, all use cases of `read_command()` [0, 1],
in (at least) the grass-addons repository, do not consider an output
from `r.category` which includes labels.
[0]
https://grass.osgeo.org/grass74/manuals/libpython/script.html?highlight=read_
1: https://docs.scipy.org/doc/numpy/user/basics.io.genfromtxt.html
-Original Message-
From: grass-dev On Behalf Of Nikos
Alexandris
Sent: søndag 19. august 2018 22:19
To: GRASS-GIS development mailing list
Subject: [GRASS-dev] Parsing output of r.category which includes labels
If I am not wrong, all use
If I am not wrong, all use cases of `read_command()` [0, 1],
in (at least) the grass-addons repository, do not consider an output
from `r.category` which includes labels.
[0]
https://grass.osgeo.org/grass74/manuals/libpython/script.html?highlight=read_command#script.core.read_command
[1]
https:
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