On 17 May 2017 at 11:27, Sören Gebbert wrote:
> Hi Luca,
>
> 2017-05-17 11:11 GMT+02:00 Luca Delucchi :
>> On 17 May 2017 at 11:03, Sören Gebbert wrote:
>>> Hi Luca,
>>>
>>
>> Hi,
>>
>>>
>>> In case of mean values
Hi Luca,
2017-05-17 11:11 GMT+02:00 Luca Delucchi :
> On 17 May 2017 at 11:03, Sören Gebbert wrote:
>> Hi Luca,
>>
>
> Hi,
>
>>
>> In case of mean values i would prefer the calculated mean of the
>> Gregorian calendar that is the base of the
On 17 May 2017 at 11:03, Sören Gebbert wrote:
> Hi Luca,
>
Hi,
>
> In case of mean values i would prefer the calculated mean of the
> Gregorian calendar that is the base of the temporal framework:
>
> 1 year = 365.2425 days
> 1 month = 30.436875 days
> 6 months =
Hi Luca,
2017-05-17 10:51 GMT+02:00 Luca Delucchi :
> On 17 May 2017 at 10:08, Sören Gebbert wrote:
>> Hi Luca,
>>
>
> Hi Soeren,
>
>>
>> 2017-05-17 9:36 GMT+02:00 Luca Delucchi :
>>> Hi devs, Soeren
>>>
>>> I'm looking
On 17 May 2017 at 10:08, Sören Gebbert wrote:
> Hi Luca,
>
Hi Soeren,
>
> 2017-05-17 9:36 GMT+02:00 Luca Delucchi :
>> Hi devs, Soeren
>>
>> I'm looking for a function that return the number of minutes, days,
>> months, years according the
Hi Luca,
2017-05-17 9:36 GMT+02:00 Luca Delucchi :
> Hi devs, Soeren
>
> I'm looking for a function that return the number of minutes, days,
> months, years according the granularity, for example "2 months" should
> return 60 days and "1 years" could return 12 months or 365
Hi devs, Soeren
I'm looking for a function that return the number of minutes, days,
months, years according the granularity, for example "2 months" should
return 60 days and "1 years" could return 12 months or 365 days.
does it exist a function like that or could I add it to