Tyler,
Well, that's simply brilliant. I knew it should be easy. Plus,
when I tested it I found out my rasters weren't truly mutually exclusive
after all, as some cells = 3. This is apparently an artifact of
v.to.rast polygon boundary issues but it's a pretty small problem.
Nonethe
Dave Roberts wrote:
>Colleagues,
>
>I know this must be easy, but I haven't found it.
>
> Suppose I have three grids (a, b, and c) where each grid is 0 or 1,
>and the 1s are mutually exclusive. I want a new grid where if grid
>a=1 then newgrid = 1; if grid b=1 then new grid = 2; if grid c=
Friends,
I did get an off-list solution (thanks Jiao) that works for two
rasters but not for n (using the implied else).
I think what GRASS needs is an r.update routine that works like an
SQL update statement, i.e.
r.update map=composite.map value=1 where="map a = 1"
r.update map=comp
Colleagues,
I know this must be easy, but I haven't found it.
Suppose I have three grids (a, b, and c) where each grid is 0 or 1,
and the 1s are mutually exclusive. I want a new grid where if grid
a=1 then newgrid = 1; if grid b=1 then new grid = 2; if grid c=1 then
newgrid = 3.
S
