Is there a mod_haskell (like mod_perl and mod_python) for Apache HTTP
server? Does anyone know about it?
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Hi everyone -
I'm very much a Haskell newbie, but have followed Haskell (and the
various Haskell sites) for quite a few months now, and I absolutely
*love* the language.
One thing that **fascinated** me a while ago was the site which gave
Haskell code for a "Haskell-based fileserver/OS" using
Robert Dockins wrote:
On Sunday 30 July 2006 07:47, Brian Hulley wrote:
Another option, is the Edison library which uses:
class (Functor s, MonadPlus s) => Sequence s where
so here MonadPlus is used instead of Monoid to provide empty and
append. So I've got three main questions:
1) Did
On 30.07 12:12, Jason Dagit wrote:
> Depending on the type of sandboxing that you need/want #2 might be
> possible with GHC. Take lambdabot for example. lambdabot has made it
> safe to allow arbitrary expression evaluation by disallowing IO and
> not importing unsafePerformIO and similar "unsafe"
Florian Weimer wrote:
>
> * SevenThunders:
>
>> OK it was stupid. Apparently GHC behaves differently according to what
>> the
>> name of the high level source file is. If I renamed test.hc to main.hc
>> everything works the same as GHCi. I probably should actually read the
>> manual some day
Yes I do have another test on my path. It is in a utilities directory of
unix like commands that have been ported to windows. However I also have a
test.exe that was created by ghc that seems to do nothing, even if I type
./test.exe. Thanks for the hint though.
--
View this message in context:
On 7/30/06, Einar Karttunen wrote:
On 29.07 14:07, Brian Sniffen wrote:
> I'm very excited by the ability to pass functions or IO actions
> between threads of the same program. But I don't see any language or
> library support for doing so between programs, or between sessions
> with the same p
On Sunday 30 July 2006 07:47, Brian Hulley wrote:
> Hi -
>
> Part 1 of 2 - Monoid versus MonadPlus
> ===
>
> I've just run into a troublesome question when trying to design a sequence
> class:
>
> class ISeq c a | c -> a where
> empty :: c
> single :: a
Yes, Char is in the haskell98 package, the new name for Char is
Data.Char which exports a bit more. Either add haskell98 as a package,
or replace Char with Data.Char (which is in base), I'd recommend the
latter, but either should work.
Thanks
Neil
a ha, that works, thank you both very much,
Hi
so basically I was expecting 'Char' to be in the 'base' package, I guess
this is wrong?
Yes, Char is in the haskell98 package, the new name for Char is
Data.Char which exports a bit more. Either add haskell98 as a package,
or replace Char with Data.Char (which is in base), I'd recommend the
The Text.ParserCombinators.Parsec modules are in the parsec module.
build-depends: base
Add parsec here:
build-depends: base, parsec
The reason it works when you run it without -hide-all-packages is that
by default for convenience all packages are 'exposed'. That is they can
be
On Sun, 2006-07-30 at 13:22 +0100, Jón Fairbairn wrote:
> Duncan Coutts <[EMAIL PROTECTED]> writes:
>
> > On Sun, 2006-07-30 at 10:56 +0100, Jón Fairbairn wrote:
> > > "David House" <[EMAIL PROTECTED]> writes:
> > > > 1) f is strict iff f _|_ = _|_.
> > > > 2) f is strict iff it forces evaluation
On Sun, 2006-07-30 at 15:01 +0100, allan wrote:
> however with version 6.4.2 I get the following error:
>
> haskellprint$ ./Setup.hs build
> Preprocessing executables for haskellprint-0.1...
> Building haskellprint-0.1...
> Chasing modules from: Main.hs
> Could not find module `Text.ParserCombin
Hello all,
(before I start I should say I'm relatively new (a few months) to
haskell, so I'm not exactly savvy with the use of the compilers)
I have a problem using the cabal with version 6.4.2 of ghc, the same
thing occurs with two projects which I wish to compile, I'll use the
simplest one
Duncan Coutts <[EMAIL PROTECTED]> writes:
> On Sun, 2006-07-30 at 10:56 +0100, Jón Fairbairn wrote:
> > "David House" <[EMAIL PROTECTED]> writes:
> > > 1) f is strict iff f _|_ = _|_.
> > > 2) f is strict iff it forces evaluation of its arguments.
> >
> > In (2), you have to be evaluating f on an
On Sun, 2006-07-30 at 10:56 +0100, Jón Fairbairn wrote:
> "David House" <[EMAIL PROTECTED]> writes:
>
> > Hi all.
> >
> > I've seen two definitions of a 'strict function', which I'm trying to
> > unite in my mind:
> >
> > 1) f is strict iff f _|_ = _|_.
> > 2) f is strict iff it forces evaluatio
* SevenThunders:
> OK it was stupid. Apparently GHC behaves differently according to what the
> name of the high level source file is. If I renamed test.hc to main.hc
> everything works the same as GHCi. I probably should actually read the
> manual some day.
Some operating systems have a "test
On 30/07/06, Ian Lynagh <[EMAIL PROTECTED]> wrote:
If the value of (id x) is demanded then the value of x will always be
demanded. Therefore id is strict in its first argument.
...
In place of your 2), I would say
(f x0 .. xn) is strict in xi if demanding the value of (f x0 .. xn)
requires
Hi -
Part 1 of 2 - Monoid versus MonadPlus
===
I've just run into a troublesome question when trying to design a sequence
class:
class ISeq c a | c -> a where
empty :: c
single :: a -> c
append :: c -> c -> c
However I've noticed that people
On Sun, Jul 30, 2006 at 09:44:25AM +0100, David House wrote:
>
> I've seen two definitions of a 'strict function', which I'm trying to
> unite in my mind:
>
> 1) f is strict iff f _|_ = _|_.
> 2) f is strict iff it forces evaluation of its arguments.
>
> There is a large sticking point that in m
"David House" <[EMAIL PROTECTED]> writes:
> Hi all.
>
> I've seen two definitions of a 'strict function', which I'm trying to
> unite in my mind:
>
> 1) f is strict iff f _|_ = _|_.
> 2) f is strict iff it forces evaluation of its arguments.
>
> There is a large sticking point that in my minds
On 29.07 14:07, Brian Sniffen wrote:
> I'm very excited by the ability to pass functions or IO actions
> between threads of the same program. But I don't see any language or
> library support for doing so between programs, or between sessions
> with the same program. OCaml provides a partial solu
Hi all.
I've seen two definitions of a 'strict function', which I'm trying to
unite in my mind:
1) f is strict iff f _|_ = _|_.
2) f is strict iff it forces evaluation of its arguments.
There is a large sticking point that in my minds seems to fit (1) but
not (2): id. Clearly, id undefined is
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