Might better ways, but the following work:
length [c | x <- [1..100], let c = chain x , length c > 15]
length [c | x <- [1..100], c <- [chain x] , length c > 15]
On Wed, Feb 16, 2011 at 9:19 AM, Tako Schotanus wrote:
> Hello,
>
> I was going through some of the tuturials and trying out differe
Ah yes, this is very very very helpful. Thanks : )
Miguel's example is not quite as idiomatic, but...for some reason I
find it beguiling nonetheless.
On Thu, Dec 17, 2009 at 2:36 PM, Roman Leshchinskiy
wrote:
> On 18/12/2009, at 00:37, Stephen Lavelle wrote:
>
>> Given
>
Given
class MyClass k where
type AssociatedType k :: *
Is there a way of requiring AssociatedType be of class Eq, say?
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